There are a multitude of possible orbits and low circular orbits take more delta V to enter and exit. A science fiction writer using 6 km/s for Earth orbit to Mars orbit has a needlessly high delta V budget.

There are capture orbits that take much less delta V to enter and exit. By capture orbit I mean a periapsis as low as possible and apoapsis as high as possible. A capture orbit's apoapsis should be within a planet's Sphere Of Influence (SOI).

On page 124 of Prussing and Conway's Orbital Mechanics, radius of Sphere Of Influence is given by:

r

_{soi}= ( m

_{p}/ m

_{s})

^{2/5}r

_{sp}

where

r

_{soi}is radius of Sphere Of Influence

m

_{p}is mass of planet

m

_{s}is mass of sun

r

_{sp}is distance between sun and planet.

The table below is modeled after a mission table at Atomic Rockets, a popular resource for science fiction writers and space enthusiasts.

• Departure and destination planets are along the left side and across the top of the table.

• Numbers are kilometers/second

• Numbers below the diagonal in blue are delta V's needed to go from departure planet's low circular orbit to destination planet's low circular orbit. These are about the same as the blue quantities listed at Atomic rockets.

• Numbers above the diagonal in red are delta V's needed to go from departure planet's capture orbit to desitnation planet's capture orbit.

Venus | Earth | Mars | Jupiter | Saturn | Uranus | Neptune | |

Venus | .7 | 3.6 | 5.6 | 6.7 | 7.5 | 7.5 | |

Earth | 6.8 | 1.1 | 3.5 | 4.6 | 5.3 | 5.4 | |

Mars | 7.9 | 5.7 | 3.0 | 4.5 | 5.6 | 5.8 | |

Jupiter | 25.8 | 24.0 | 21.8 | .1 | .3 | .3 | |

Saturn | 20.0 | 18.1 | 16.2 | 27.8 | .1 | .2 | |

Uranus | 16.6 | 14.7 | 13.2 | 23.8 | 16.6 | .03 | |

Neptune | 17.3 | 15.4 | 14.1 | 24.5 | 17.3 | 13.1 |

It's easy to see the red numbers are a lot less than the blue numbers. I used this spreadsheet to get these numbers. The spreadsheet assumes circular, coplanar orbits.

A graphic comparing delta Vs from earth to various destination planets:

If a low circular orbit at the destination is needed, it's common to do a burn to capture orbit with the capture orbit's periapsis passing through the upper atmosphere. Each periapsis pass through the upper atmosphere sheds velocity, lowering the apoapsis. Thus over time the orbit is circularized without the need for reaction mass. The planets in the table above have atmospheres, so the drag pass technique can be used for all of them.

A delta V budget is from propellant source to destination. If propellant depots are in high orbit, the needed delta V is closer to departing from a capture orbit than departing from a low circular orbit.

Thus it would save a lot of delta V to depart from Earth-Moon-Lagrange 1 or 2 (EML1 or EML2) regions. The poles of Luna have cold traps that may have rich volatile deposits. This potential propellant is only 2.5 km/s from EML1 and EML2. Entities like Planetary Resources have talked about parking a water rich asteroid at EML1 or 2. Whether EML propellant depots are supplied by lunar or asteroidal volatiles, they would greatly reduce the delta V for interplanetary trips.

Mars' two moons, Phobos and Deimos, have low densities. Whether that is from volatile ices or voids in a rubble pile is still unknown. If they do have volatile ices, these moons could be a propellant source. It would take much less delta V departing from Deimos than low Mars orbit.

All the gas giants have icey bodies high on the slopes of their gravity wells. However the axis of Uranus and her moons are tilted 97 degrees from the ecliptic. The plane change would be very expensive in terms of delta V. So the moons of Uranus wouldn't be helpful as propellant sources.

Venus has no moon. So of all the planets listed above, only Uranus and Venus lack potential high orbit propellant sources.

Anyway you look at it, the blue numbers from conventional wisdom are inflated.

## 8 comments:

Thanks for the post. . Helped me verify my numbers. Cheers

You're welcome.

I was surprised when I first calculated delta Vs from and to high apogee elliptical parking orbits. Didn't believe it at first and redid the calculations several times. I expect that's a common reaction.

Interesting work, thanks for posting it. Adding another chart for Earth's surface to those orbits or from LEO to those orbits would be handy as well, though both should just be a constant added to the existing chart.

Mercury is interesting from a science fiction perspective in that it has polar volatiles and areas that maintain room temperature underground. Beyond the moon, it is the closest destination that has that.

Regarding this: "However the axis of Uranus and her moons are tilted 97 degrees from the ecliptic. The plane change would be very expensive in terms of delta V. So the moons of Uranus wouldn't be helpful as propellant sources."

Plane change delta-v only applies inside the system. You don't have to do a plane change to escape a moon of Uranus to Earth, nor to enter it. You lose the velocity you might have from the orbital velocity of the moon around the planet, but if you do burns to arrive and to leave then that's a wash.

Thanks so much for the post and spreadsheet! Used it as a reference for a project and gave me some ideas. Your work is much appreciated.

Hi David,

Just playing with your spreadsheet in regard to min Dv Earth<>Mars using Capture orbits.

Assuming aerobraking at each end, can the spreadsheet calc the ascent Dv necessary to entry the capture orbits at the Earth & Mars ends?

If not can you please point me in the direction to find the ascent Dvs?

Thanks,

Phil

Phil,

Cells

J40andJ41are apoapsis and periapsis circularize burns.Orbits are time reversible so these same burns are what it takes to go from the circular orbit to the elliptical orbit.

For example, if I set earth periapsis at 300 and apoapsis at 9119690 (SOI altitude) I get circulize burns .5795 and 3.16. It'd cost 3.16 km/s to go from LEO to a 9119690 km altitude apogee.

Likewise from a 911969 circular orbit, it would take .5795 km/s to dropp to a 300 km perigee.

Hello,

I've just wanted to ask, whether it is possible to reduce delta v even further by using aerocapture technology?

Say you depart from Jupiter (from jupiter's capture orbit) and you are heading to Earth. Could you, instead of parking your spaceship on Earth's capture orbit, enter earth's atmosphere and slow down the ship putting it on LEO and then land on Earth. Could this reduce the delta v (Jupiter Earth) from your 3.5 km/sec to say 2km per sec or so?

Trident,

My lower delta Vs assume a capture orbit with periapsis in the upper atmosphere. Which slows down the craft each periapse pass through the atmosphere. So aerobraking is already assumed in my numbers.

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